18x^2=-3x+28

Solution for 18x^2=-3x+28 equation:

18x^2=-3x+28

We move all terms to the left:

18x^2-(-3x+28)=0

We get rid of parentheses

18x^2+3x-28=0

a = 18; b = 3; c = -28;
Δ = b2-4ac
Δ = 32-4·18·(-28)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-45}{2*18}=\frac{-48}{36}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+45}{2*18}=\frac{42}{36}
=1+1/6
$